log[2](x-4)-log[2](x+3)=8

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Solution for log[2](x-4)-log[2](x+3)=8 equation:


Simplifying
log[2](x + -4) + -1log[2](x + 3) = 8

Reorder the terms:
glo * 2(-4 + x) + -1log[2](x + 3) = 8

Reorder the terms for easier multiplication:
2glo(-4 + x) + -1log[2](x + 3) = 8
(-4 * 2glo + x * 2glo) + -1log[2](x + 3) = 8
(-8glo + 2glox) + -1log[2](x + 3) = 8

Reorder the terms:
-8glo + 2glox + -1glo * 2(3 + x) = 8

Reorder the terms for easier multiplication:
-8glo + 2glox + -1 * 2glo(3 + x) = 8

Multiply -1 * 2
-8glo + 2glox + -2glo(3 + x) = 8
-8glo + 2glox + (3 * -2glo + x * -2glo) = 8
-8glo + 2glox + (-6glo + -2glox) = 8

Reorder the terms:
-8glo + -6glo + 2glox + -2glox = 8

Combine like terms: -8glo + -6glo = -14glo
-14glo + 2glox + -2glox = 8

Combine like terms: 2glox + -2glox = 0
-14glo + 0 = 8
-14glo = 8

Solving
-14glo = 8

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '-14lo'.
g = -0.5714285714l-1o-1

Simplifying
g = -0.5714285714l-1o-1

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